A Aaron de256 New member Joined Oct 15, 2022 Messages 1 Oct 15, 2022 #1 Given that tanφ -3 = 0 evaluate, 4 sinφ -2cosφ Without using tables or calculators if φ lies between 180° and 270°
Given that tanφ -3 = 0 evaluate, 4 sinφ -2cosφ Without using tables or calculators if φ lies between 180° and 270°
D Deleted member 4993 Guest Oct 15, 2022 #2 Aaron de256 said: Given that tanφ -3 = 0 evaluate, 4 sinφ -2cosφ Without using tables or calculators if φ lies between 180° and 270° Click to expand... One of the way: Hint: tan ^2(x) = sec^2(x) - 1...... Continue
Aaron de256 said: Given that tanφ -3 = 0 evaluate, 4 sinφ -2cosφ Without using tables or calculators if φ lies between 180° and 270° Click to expand... One of the way: Hint: tan ^2(x) = sec^2(x) - 1...... Continue
Dr.Peterson Elite Member Joined Nov 12, 2017 Messages 16,863 Oct 15, 2022 #3 Aaron de256 said: Given that tanφ -3 = 0 evaluate, 4 sinφ -2cosφ Without using tables or calculators if φ lies between 180° and 270° Click to expand... Another approach: Sketch the reference triangle for this angle, and use it to find the values of sinφ and cosφ.
Aaron de256 said: Given that tanφ -3 = 0 evaluate, 4 sinφ -2cosφ Without using tables or calculators if φ lies between 180° and 270° Click to expand... Another approach: Sketch the reference triangle for this angle, and use it to find the values of sinφ and cosφ.