Princezz3286 said:

a: the directions are to divide: 6c^3 + 7c^2 - 38c + 24 / 3c - 4

As posted, the above means the following:

. . . . .\(\displaystyle 6c^3\, +\, 7c^2\, -\, 38c\, +\, \frac{24}{3x}\, -\, 4\)

Is this what you meant? Or did you mean the following?

. . . . .\(\displaystyle \frac{6c^3\, +\, 7c^2\, -\, 38c\, +\, 24}{3c\, -\, 4}\)

Or something else?

Have you learned how to do

**long polynomial division** yet?

Princezz3286 said:

b: for this problem it says to multiply and simplify: w^2 - 3w -54/w^3 - 8w^2 X w/(w + 6)

I think you are using the variable "X" to indicate multiplication, and I think you omitted grouping symbols, so the above is meant actually to be as follows:

. . . . .\(\displaystyle \left(\frac{w^2\, -\, 3w\, -\, 54}{w^3\, -\, 8w^2}\right)\, \left(\frac{w}{w\, +\, 6}\right)\)

Your work done appears to have been as follows:

. . . . .\(\displaystyle \left(\frac{(w\, -\, 9)(w\, +\, 6)}{w^2(w\, -\, 8)}\right)\, \left(\frac{w}{w\, +\, 6}\right)\)

. . . . .\(\displaystyle \left(\frac{w\, -\, 9}{w^2(w\, -\, 8)}\right)\, \left(\frac{w}{1}\right)\)

. . . . .\(\displaystyle \left(\frac{w\, -\, 9}{w(w\, -\, 8)}\right)\, \left(\frac{1}{1}\right)\)

. . . . .\(\displaystyle \frac{w\, -\, 9}{w(w\, -\, 8)}\)

How are you getting "-9w" as a numerator?

Please reply showing those steps (or correcting my guesses above). Thank you!

Eliz.