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If 3 of 20 tyres are defective and 4 of them are randonly chosen for inspection, what is the probablity that only one of the defective tyres are included?

If the problem is "the probablity that only one of the defective tyres are included" then the book is wrong. I haven't done the calculations but I suspect that the book is giving the probability that "at least one tyre is defective".

If 3 of 20 tyres are defective and 4 of them are randonly chosen for inspection, what is the probablity that only one of the defective tyres are included?
My Attempt:
= (3C1 * 17C3) / 20C4
= 0.4211 Book Answer: 0.889