#### emmaiskool242

##### Junior Member

- Joined
- Mar 29, 2006

- Messages
- 66

Pythagorean Theorem=a^2 + b^2=c^2

C=hypotenuse

ok so here is my work so far~

6^2+10^2=c^2

36+100=c^2

136=c^2

So that is how far I have gotten

Can anyone help me??

- Thread starter emmaiskool242
- Start date

- Joined
- Mar 29, 2006

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Pythagorean Theorem=a^2 + b^2=c^2

C=hypotenuse

ok so here is my work so far~

6^2+10^2=c^2

36+100=c^2

136=c^2

So that is how far I have gotten

Can anyone help me??

emma, are you sure b=10? CHECK to make sure; could be b=8.emmaiskool242 said:Use the Pythagorean Theorem to find the hypotenuse of a right-angled triangle if side a=6 and side b=10.

- Joined
- Mar 29, 2006

- Messages
- 66

but if i leave it in square root form then i got

B=2(square root)2*17

B=2(square root)34

i think that Im supposed to leave it in square root form so did I get that right???