Quadratic eqns: y=X^2-2x-8 and y=-2x^2-x+2

rn50nurse

New member
Joined
Aug 5, 2007
Messages
22
y=X^2-2x-8 and y=-2x^2-x+2

I am lost how to start this to find the vertex and points for the parabola. anyone Help? thanks!
 

galactus

Super Moderator
Staff member
Joined
Sep 28, 2005
Messages
7,216
Finding the vertex is easy.

You have \(\displaystyle \L\\x^{2}-2x-8\)

a=1, b=-2, c=-8

To find the vertex, \(\displaystyle \L\\x=\frac{-b}{2a}\)

\(\displaystyle \L\\y=c-\frac{b^{2}}{4a}\)
 

rn50nurse

New member
Joined
Aug 5, 2007
Messages
22
I think I had a "brain fart" thanks for the input-- :lol:
 
Top