We have 2x^2-(a+b)x+2a-b=0 and x^2+(a-b-1)x+a-2b-1=0
For wich values of a and b the two equations have the same solutions?
Solution:
a=4/9 b=-2/3
You plugged each quadratic into the Quadratic Formula. You obtained results in terms of "a" and "b". And... then what?We have 2x^2-(a+b)x+2a-b=0 and x^2+(a-b-1)x+a-2b-1=0
For which values of a and b the two equations have the same solutions?
Solution: a=4/9 b=-2/3
We have 2x^2-(a+b)x+2a-b=0 and x^2+(a-b-1)x+a-2b-1=0
For wich values of a and b the two equations have the same solutions?
Solution:
a=4/9 b=-2/3
No .... you do not need trial and error method here.yes those are right values.
if u have multiple choice answer then you need to do hit n trial.
and you need to put each value in equation n see are those two have same solution.
One way would be:We have 2x^2-(a+b)x+2a-b=0 and x^2+(a-b-1)x+a-2b-1=0
For which values of a and b the two equations have the same solutions?
Solution:
a=4/9 b=-2/3