A abbyhart New member Joined Feb 25, 2008 Messages 1 Feb 25, 2008 #1 a quadratic function is given by y=a(x-1)squared + k given two points on the parabola (-1, -11/2) and (1/2, 1/8) find the values of a and k. -11/2 = a(-1-1) squared + k -11/2 = 4a +k 1/2 = a(1/8-1)squared + k 1/2 = a (-19/16) + k -11/2 = 4a + k 1/2 = -19/16 +k = -6 = 83a/16 ?

a quadratic function is given by y=a(x-1)squared + k given two points on the parabola (-1, -11/2) and (1/2, 1/8) find the values of a and k. -11/2 = a(-1-1) squared + k -11/2 = 4a +k 1/2 = a(1/8-1)squared + k 1/2 = a (-19/16) + k -11/2 = 4a + k 1/2 = -19/16 +k = -6 = 83a/16 ?

L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Feb 25, 2008 #2 Looks to me like you interchanged the x and y values of the second point. I think the second equation should be 1/8 = (1/4)a + k.

Looks to me like you interchanged the x and y values of the second point. I think the second equation should be 1/8 = (1/4)a + k.