Question...Help?

im_fed_up

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Sep 4, 2005
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Can anyone help me?

The average patient cost C to a community hospital per day in the US from 1989 to 1996 can be modeled by: C= -2.37t^2+66.44t+696.39

where t is the time in years, with t=0 corresponding to 1990.

Question: Determine algebraically when the average cost exceeded $900 per day?


--I know the answer is during 1993 i just dont know how to get it
 
Solve the inequality −2.37t<SUP>2</SUP>+66.44t+696.39>900.
The solution set is approx. 3.5<t<24.5.
 
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