\(\displaystyle z=\frac{(900-880)\sqrt{100}}{150}=4/3 = 1.33\)

Looking in the table we see .9082. But this would be 'less than' 880 because the z values approach from the left.

Since it is asking for 'greater than' 900, we subtract from 1 and get

1-.9082=.0918.

In other words, if we sampled 100 apartments in NYC, there would be a little more than a 9% chance that the rent would be more than $900. This seems rather counterintuitive.