Hi guys! Here's the problem,
George drew a rectangle with an area of 84cm squared. If the lengh is 8cm more than the width, what is the length and width of the rectangle?
Now I know the answer is 14 and 6 from just looking at it, 14 x 6 = 84! But I can't work it out. Here's my attempt.
Two equations, L = length , W = width
W + 8 = L and (W+8) x L = 84
So plugging L in to the second equation we have
(W + 8 ) ( W + 8) = 84
W^2 + 16 W + 64 = 84
W^2 +16W = 20
As a quadratic this is like 9.1 or something. I must be missing something simple! Please help!
Thanks, Dave
George drew a rectangle with an area of 84cm squared. If the lengh is 8cm more than the width, what is the length and width of the rectangle?
Now I know the answer is 14 and 6 from just looking at it, 14 x 6 = 84! But I can't work it out. Here's my attempt.
Two equations, L = length , W = width
W + 8 = L and (W+8) x L = 84
So plugging L in to the second equation we have
(W + 8 ) ( W + 8) = 84
W^2 + 16 W + 64 = 84
W^2 +16W = 20
As a quadratic this is like 9.1 or something. I must be missing something simple! Please help!
Thanks, Dave