rectangular plate

[logistic_guy]

A rectangular plate with a width of \(\displaystyle 16\) m and a height of \(\displaystyle 12\) m is located \(\displaystyle 4\) m below a water surface. The plate is tilted and makes a \(\displaystyle 35°\) angle with the horizontal. The resultant hydrostatic force acting on the top surface of this plate is

(a) \(\displaystyle 10800\) kN
(b) \(\displaystyle 9745\) kN
(c) \(\displaystyle 8470\) kN
(d) \(\displaystyle 6400\) kN
(e) \(\displaystyle 5190\) kN

 

[khansaheb]

A rectangular plate with a width of \(\displaystyle 16\) m and a height of \(\displaystyle 12\) m is located \(\displaystyle 4\) m below a water surface. The plate is tilted and makes a \(\displaystyle 35°\) angle with the horizontal. The resultant hydrostatic force acting on the top surface of this plate is

(a) \(\displaystyle 10800\) kN
(b) \(\displaystyle 9745\) kN
(c) \(\displaystyle 8470\) kN
(d) \(\displaystyle 6400\) kN
(e) \(\displaystyle 5190\) kN

show us your effort/s to solve this problem.

 

[mmmladenov1]

Dating for Sex.

 

[bhuvanesh249]

Dating for Sex.

 

[logistic_guy]

This problem can be solved by the Hydrostatic force formula.

\(\displaystyle F_R = \rho g\left(s + \frac{b}{2}\right)\sin\theta \ ab\)

\(\displaystyle = 1000(9.81)\left(4 + \frac{12}{2}\right)\sin 35^{\circ} \ (16)(12) \approx 1.08 \times 10^7 \ \text{N} = 108000 \times 10^3 \ \text{N} = 108000 \ \text{kN}\)