Show that {Trigonometric identities}

G

Guest

Guest
The question is to show that

sin theta + 2 sin^3theta + sin ^5 theta /(sin 3 theta + 2 sin 5 theta + sin 7 theta)=sin 3 theta/ sin 5 theta

thanks
 
[sin@+2sin^3@+sin^5@] / [s^3@+2sin^5@+sin^7@] = sin^3@/sin^5@
factor sin^2@ from denominator
[sin@+2sin^3@+sin^5@] /[sin^2@[sin@+2sin^3@+sin^5@]]=
cancel likes
1/sin^2@=
multiply by sin^3@/sin^3@
sin^3@/sin^5@ = proof

Arthur
 
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