- Thread starter fedwards
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What have you tried? How far have you gotten? You've applied the exponent properties that you've learned (and memorized, I hope!). Where are you stuck?fedwards said:(2xy)^2 over or divided by (-2xy)^3

Can you help me simplify this?

Please be complete. Thank you!

Eliz.

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Use the Power of a Product rule as step one in the numerator and denominator.fedwards said:(2xy)^2 over or divided by (-2xy)^3

Can you help me simplify this?

I will use the letters a, b and x to show you how the rule works.

(ab)^x = a^x times b^x

Your question:

(2xy)^2 becomes 4x^2y^2 = our numerator.

(-2xy)^3 becomes -8x^3y^3 = our denominator.

We have this new fraction:

(4x^2y^2)/(-8x^3y^3)

We now reduce the fraction to the lowest term

4/-8 becomes -1/2.

x^2/x^3 becomes 1/x.

y^2/y^3 becomes 1/y.

We now have this new fraction as a final answer:

-1/2xy

Done!

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Never mind, I guess. Now you can just copy the complete solution, posted above. :roll:stapel said:What have you tried? How far have you gotten? You've applied the exponent properties that you've learned (and memorized, I hope!). Where are you stuck?

Please be complete. Thank you!

Eliz.