Simple arithmetic problem, comparing to book.

[4lex]

Hi,
first post here: trying to see why I'm unable to get the same answer as the solution provided in the back of an algebra book. Please help me solve the following fraction:

13+(−3)^2 +4(−3)+1−[−10−(−6)]
-----------------------------------------
{[4+5]÷[4^2−3^2(4−3)−8]}+12

I get 15/3 = 5
book says answer is 3. Any suggestions? Thanks!

 

[jonah2.0]

Don't worry about it. You're right. It's a typo.

 

[John Marsh]

Solution

Given {13+(−3)^2 +4(−3)+1−[−10−(−6)]}/{{[4+5]÷[4^2−3^2(4−3)−8]}+12}

First solve numerator
13+(−3)^2 +4(−3)+1−[−10−(−6)]
13+(−3)^2 +4(−3)+1−[−10+6]
13+(−3)^2 +4(−3)+1−[−4]
13+(−3)^2 +4(−3)+1+4
13+(−3)^2 -12+1+4
13+9-12+1+4
15

Solve denominator
{[4+5]÷[4^2−3^2(4−3)−8]}+12
{[9]÷[4^2−3^2(4−3)−8]}+12
{[9]÷[4^2−3^2(1)−8]}+12
{[9]÷[16-9−8]}+12
{[9]÷[-1]}+12
-9+12
3
Hence the answer is 15/3=5​

 

[4lex]

Cool. Thanks!!!

Given {13+(−3)^2 +4(−3)+1−[−10−(−6)]}/{{[4+5]÷[4^2−3^2(4−3)−8]}+12}

First solve numerator
13+(−3)^2 +4(−3)+1−[−10−(−6)]
13+(−3)^2 +4(−3)+1−[−10+6]
13+(−3)^2 +4(−3)+1−[−4]
13+(−3)^2 +4(−3)+1+4
13+(−3)^2 -12+1+4
13+9-12+1+4
15

Solve denominator
{[4+5]÷[4^2−3^2(4−3)−8]}+12
{[9]÷[4^2−3^2(4−3)−8]}+12
{[9]÷[4^2−3^2(1)−8]}+12
{[9]÷[16-9−8]}+12
{[9]÷[-1]}+12
-9+12
3
Hence the answer is 15/3=5​

Thanks for your responses!
Took calculus in community college. Even got an A, but wow did I forget everything since 10 years ago! Great forum here! Will return for future questions. Thanks much!

 

[John Marsh]

My Pleasure

Thanks for your responses!
Took calculus in community college. Even got an A, but wow did I forget everything since 10 years ago! Great forum here! Will return for future questions. Thanks much!

Its my pleasure, I'm glad it helped you

Hungry to answer more questions, so keep on posting new questions.