- Thread starter puzzled01
- Start date

1: bring the x^3 to numerator position: (3x^-5 / 4)^-3puzzled01 said:Please help. (3x^-2 / 4x^3)^-3

2: multiply inside powers by -3: 3^-3(x^15) / 4^-3

3: bring 3^-3 to denominator, 4^-3 to numerator: 4^3(x^15) / 3^3

If you can't follow that, see your teacher...

EDIT:

> I got 64x^15 / 27 is that right?

YES! Good work :idea: