SOH-CAH-TOA help.

S

SweetyPi

New member
Joined
May 25, 2006
Messages
3
I've been trying to figure the use of these ratios and I still don't get them... I know they apply to right triangles only. I understand sine law and cosine law but I'll be damned if I can understand this... I don't know when to use them and exactly how... any help or an explanation would really be helpful so I can continue on.. I'm doing the gr. 10 advanced self study course so I can eventually get into the nursing course...but at this rate I'll be lucky to get the gr. 10!
Thanks for any help at all
 
I'm sorry..I can't post pics or anything because I don't think I have the software to post them..but teh one set of problems I'm running into are three right angled triangles triangle A, Hypotenuse is unknown, the angle across from the right angle is 34 degrees, and the side between the two is 6 cm..and I ha[/code] to solve for the opposite side (straight up and down)... I'm sorry if that doesn't make sense...I'm just confused as to when to use what one....it's all a bit confusing..but I get everything else..go figure
 
Don't go getting a heart attack, SPi; it's real easy!

Go here: http://www.mathwords.com/s/sohcahtoa.htm

If that's not enough, do a http://www.google.com search on "SOH-CAH-TOA"

Sorry, but we can't "teach" here...

Test questions:
a^2 + b^2 = c^2
Where does that come from? What does it mean?

In the triangle you give as example, one angle = 90, another = 34 : what is the 3rd?
 
sorry... mis type on the keyboard... Thank you... I'll follow that link and hopefully I'll get it..I'm sure it's simple..I just haven't wrapped my head around it yet. The angle that's missing is unknown as well. the problem is three right triangle and you have to answer with what ratios suits it best given the information. Like I said..I'm sure it's simple... but I'm making it more complicated.
 
You must log in or register to reply here.
Top