marshall1432
Banned
- Joined
- Jan 10, 2007
- Messages
- 80
Solve by completing the square:
2x'2'squared -6x-8=0
WORK DONE :
x2-3x-8=0
x2-3x-(3/2)2= -8=(3/2)2
(x-3/2)2=-8/2 +3/2
x-3/2 'plus or minus' -5/2
final answer that i got was ' x=i-5/2+3/2
2x'2'squared -6x-8=0
WORK DONE :
x2-3x-8=0
x2-3x-(3/2)2= -8=(3/2)2
(x-3/2)2=-8/2 +3/2
x-3/2 'plus or minus' -5/2
final answer that i got was ' x=i-5/2+3/2