\(\displaystyle x^2\, - \, 3x \, = \, 4\)marshall1432 said:Solve by completing the square:
WORK DONE :
x2-3x-(3/2)2= -8=(3/2)2 <-- Why is 8 negative here
x-3/2 'plus or minus' -5/2
final answer that i got was ' x=i-5/2+3/2
In a quadratic equation
\(\displaystyle ax^2 \, + \, bx \, + c = 0\)
ac < 0 --> roots are real.
marshall1432 said:I got the 3+-5
No - you did not get it. You made multiple mistakes (like using '8' instead '4') and got to the number. But your process is so misguided - it is not even wrong!
Clean up your arithmatic first - looking at the procedure I posted.
Then think about the answer and how you can simplify from there.
BUT i DON'T KNOW WHERE TO GO FROM THERE.
DO I NEED TO MULTIPLY EVERYTHING BY 2 AND DIVIDE OUT?
I think there is a serious gap in your understanding of mathematical operations. My advice for you would be to get a tutor for face-to-face instructions.