solve g(x) = xsquared - 4x + 1, g(3a) + 1, find each value

larry indians27

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can some one solve this because i have no clue what to do.

g(x)=xsquared-4x+1

g(3a)+1

find each value
 

mmm4444bot

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Re: can someone help me



I'm not sure why the instruction states to find "each" value because I only see one exercise.

A definition is provided for a function named g.

Do you understand function notation?

The symbol g(3a) is function notation; it represents the value of function g evaluated at x = 3a.

Therefore, the expression g(3a) + 1 is obtained by first evaluating function g at x = 3a and then adding 1 to the result.

We do not, in general, provide lessons at this site. If you really have no clue what to do, then perhaps you've been placed in the wrong course.

Do you know how to do basic algebra? For examples, do you know how to complete the following multiplications?

(3a)^2 = ?

4(3a) = ?

CLICK HERE FOR LESSONS ON FUNCTION NOTATION.

If, after reading over these lessons, you still cannot evaluate function g at x = 3a, then please come back and tell us why, so that we may know how to help you further.

Cheers,

~ Mark :)

 

fasteddie65

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g(x) = x^2 - 4x + 1

g(3a) + 1 = [(3a)^2 - 4(3a) + 1] + 1 = a^2 - 12a + 2
 

fasteddie65

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g(x) = x^2 - 4x + 1

g(3a) + 1 = [(3a)^2 - 4(3a) + 1] + 1 = 9a^2 - 12a + 2

OOP! for the last entry. I forgot the 9...
 

mmm4444bot

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I just learned that Fast Eddie knows how to do this exercise; I may never learn anything more about the original poster's abilities.

~ Mark :|



"Spoon feeding, in the long run, teaches us nothing but the shape of the spoon." ~ E. M. Forster

 

larry indians27

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since your so smart can you tell me if this is right

g(x)=xsquared-4x+1 find each value

g(a)+1

I came up with 2 as an answer
 

mmm4444bot

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larry indians27 said:
... since your [sic] so smart can you tell me if this is right ? Are you trying to address an individual?

g(x) = x[sup:3qtxgejg]2[/sup:3qtxgejg] - 4x + 1 ...

Find g(a) + 1

I came up with 2 as an answer


Larry:

The only way that we can say g(a) = 1 is if we know that a = 0.

Did somebody tell you that a = 0?

~ Mark :?

 

larry indians27

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adress an individual?
 

mmm4444bot

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larry indians27 said:
adress an individual?


To whom are you speaking when you use the pronoun "you"?

Also, how old are you? Is English your native language?

Cheers,

~ Mark :)

 

larry indians27

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i wasn't trying to be a smart elleck sorry if it sounded like it.
 

mmm4444bot

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It seems to me that you do not understand functions.

Please show your work, so that I may see how you arrived at the following.

g(a) + 1 = 2

 

larry indians27

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3a+1=xsquared-4x+1
3a+3a squared-4(3a)+2
3a squared-12a+2
3a+9a-12a+2
12a-12a+2
2


I have no clue if it's right
 

mmm4444bot

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larry indians27 said:
... smart elleck ... ? "smart aleck" -- named, perhaps, after the 19th-century con man Aleck Hoag


Is English your native language, Larry?

 

larry indians27

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yes, im sorry i misspelled a word
 

mmm4444bot

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larry indians27 said:
3a + 1 = x[sup:1jqxkrpa]2[/sup:1jqxkrpa] - 4x + 1 ? Where did this equation come from?


Are you changing the exercise? The equation you typed has nothing to do with evaluating g(a) + 1.

~ Mark :?

 

mmm4444bot

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larry indians27 said:


You've done more than misspell one word, but thank you for answering the question about your native language.

How old are you?

From what class does this exercise come?

Did you read the previous lesson on function notation?

DO YOU UNDERSTAND FUNCTIONS?

 

larry indians27

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The directions state, "g(x)=xsquared-4x+1, find each value"

the question is g(3a)+1
 

larry indians27

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Algebra 1
 

mmm4444bot

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larry indians27 said:
The directions state, "g(x)=xsquared-4x+1, find each value"

the question is g(3a)+1


Ah, I now understand that you are returning to the original exercise.

I will forget about g(a) + 1.

What is it that you do not understand about the complete solution to your original exercise which is written by Fast Eddie in this thread?

 

larry indians27

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did I get it right?
 
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