# solve g(x) = xsquared - 4x + 1, g(3a) + 1, find each value

#### larry indians27

##### New member
can some one solve this because i have no clue what to do.

g(x)=xsquared-4x+1

g(3a)+1

find each value

#### mmm4444bot

##### Super Moderator
Staff member
Re: can someone help me

I'm not sure why the instruction states to find "each" value because I only see one exercise.

A definition is provided for a function named g.

Do you understand function notation?

The symbol g(3a) is function notation; it represents the value of function g evaluated at x = 3a.

Therefore, the expression g(3a) + 1 is obtained by first evaluating function g at x = 3a and then adding 1 to the result.

We do not, in general, provide lessons at this site. If you really have no clue what to do, then perhaps you've been placed in the wrong course.

Do you know how to do basic algebra? For examples, do you know how to complete the following multiplications?

(3a)^2 = ?

4(3a) = ?

If, after reading over these lessons, you still cannot evaluate function g at x = 3a, then please come back and tell us why, so that we may know how to help you further.

Cheers,

~ Mark

#### fasteddie65

##### Full Member
g(x) = x^2 - 4x + 1

g(3a) + 1 = [(3a)^2 - 4(3a) + 1] + 1 = a^2 - 12a + 2

#### fasteddie65

##### Full Member
g(x) = x^2 - 4x + 1

g(3a) + 1 = [(3a)^2 - 4(3a) + 1] + 1 = 9a^2 - 12a + 2

OOP! for the last entry. I forgot the 9...

#### mmm4444bot

##### Super Moderator
Staff member

I just learned that Fast Eddie knows how to do this exercise; I may never learn anything more about the original poster's abilities.

~ Mark :|

"Spoon feeding, in the long run, teaches us nothing but the shape of the spoon." ~ E. M. Forster

#### larry indians27

##### New member
since your so smart can you tell me if this is right

g(x)=xsquared-4x+1 find each value

g(a)+1

I came up with 2 as an answer

#### mmm4444bot

##### Super Moderator
Staff member
larry indians27 said:
... since your [sic] so smart can you tell me if this is right ? Are you trying to address an individual?

g(x) = x[sup:3qtxgejg]2[/sup:3qtxgejg] - 4x + 1 ...

Find g(a) + 1

I came up with 2 as an answer

Larry:

The only way that we can say g(a) = 1 is if we know that a = 0.

Did somebody tell you that a = 0?

~ Mark :?

#### mmm4444bot

##### Super Moderator
Staff member
larry indians27 said:

To whom are you speaking when you use the pronoun "you"?

Also, how old are you? Is English your native language?

Cheers,

~ Mark

#### larry indians27

##### New member
i wasn't trying to be a smart elleck sorry if it sounded like it.

#### mmm4444bot

##### Super Moderator
Staff member

It seems to me that you do not understand functions.

Please show your work, so that I may see how you arrived at the following.

g(a) + 1 = 2

#### larry indians27

##### New member
3a+1=xsquared-4x+1
3a+3a squared-4(3a)+2
3a squared-12a+2
3a+9a-12a+2
12a-12a+2
2

I have no clue if it's right

#### mmm4444bot

##### Super Moderator
Staff member
larry indians27 said:
... smart elleck ... ? "smart aleck" -- named, perhaps, after the 19th-century con man Aleck Hoag

Is English your native language, Larry?

#### larry indians27

##### New member
yes, im sorry i misspelled a word

#### mmm4444bot

##### Super Moderator
Staff member
larry indians27 said:
3a + 1 = x[sup:1jqxkrpa]2[/sup:1jqxkrpa] - 4x + 1 ? Where did this equation come from?

Are you changing the exercise? The equation you typed has nothing to do with evaluating g(a) + 1.

~ Mark :?

#### mmm4444bot

##### Super Moderator
Staff member
larry indians27 said:

You've done more than misspell one word, but thank you for answering the question about your native language.

How old are you?

From what class does this exercise come?

Did you read the previous lesson on function notation?

DO YOU UNDERSTAND FUNCTIONS?

#### larry indians27

##### New member
The directions state, "g(x)=xsquared-4x+1, find each value"

the question is g(3a)+1

Algebra 1

#### mmm4444bot

##### Super Moderator
Staff member
larry indians27 said:
The directions state, "g(x)=xsquared-4x+1, find each value"

the question is g(3a)+1

Ah, I now understand that you are returning to the original exercise.

I will forget about g(a) + 1.

What is it that you do not understand about the complete solution to your original exercise which is written by Fast Eddie in this thread?

#### larry indians27

##### New member
did I get it right?