Solve the equation: 2/7 T^2 Minus 7/2=0

[lotus]

Solve the equation:

2/7 T^2 Minus 7/2=0

Work so far:

2T^2 over 7 Minus 7/2=0

2*2T^2 Minus 7 * 7 over 7*2=0

4T^2 Minus 49 over 14=0

Dont know what to do from here.

 

[JeffM]

Solve the equation:

2/7 T^2 Minus 7/2=0

Work so far:

2T^2 over 7 Minus 7/2=0

How do you go from

\(\displaystyle \dfrac{2}{7} * t^2 - \dfrac{7}{2} = 0\ to\ 2* 2t^2 - 7 * \dfrac{7}{7 * 2} = 0.\)

2*2T^2 Minus 7 * 7 over 7*2=0

4T^2 Minus 49 over 14=0 y

Dont know what to do from here.

.
Let's do this correctly.

\(\displaystyle \dfrac{2}{7} * t^2 - \dfrac{7}{2} = 0 \implies 7 * 2 \left (\dfrac{2}{7} * t^2 - \dfrac{7}{2} \right ) = 7 * 2 * 0 \implies\)

\(\displaystyle 2 * 2t^2 - 7 * 7 = 0 \implies 4t^2 - 49 = 0 \implies what?\)

This explains what Denis gave you, but leaves open the question of why you are confused.
If you had 4t - 49 = 0, what would you do?

 

[mmm4444bot]

2/7 T^2 Minus 7/2=0

Work so far:

2T^2 over 7 Minus 7/2=0

2*2T^2 Minus 7 * 7 over 7*2=0

4T^2 Minus 49 over 14=0

Dont know what to do from here.

Lotus, you're confusing people, by not using grouping symbols to show the correct Order of Operations.

Also, is the hyphen key on your keyboard broken?

(2*2T^2 - 7*7)/14 = 0

(4T^2 - 49)/14 = 0

Those grouping symbols are very important. :cool: