solving 1/3x + 4 + 2x + 2/3 = 2 2/3x + 1

viva_la_isabel

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Joined
Sep 10, 2006
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3
Please show me the step by step solution
i am stuck on this problem:

1/3x + 4 + 2x + 2/3 = 2 2/3x + 1

solve for x
 

stapel

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Feb 4, 2004
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viva_la_isabel said:
Please show me the step by step solution
Most of the tutors here tend to be more interested in helping you learn how to do these for yourself. So please help us help you: Post what you've tried so far, even if you think it is wrong. :D

viva_la_isabel said:
1/3x + 4 + 2x + 2/3 = 2 2/3x + 1
What you have posted could mean the following:

. . . . .\(\displaystyle \L \frac{1}{3x}\, +\, 4\, +\, 2x\, +\, \frac{2}{3}\, =\, \frac{22}{3x}\, +\, 1\)

Is this what you meant? What have you tried? How far have you gotten?

Thank you.

Eliz.
 

viva_la_isabel

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Sep 10, 2006
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ok this is how far i've gotten.

im stuck. wat do i do next?
1/3 x + 4 + 2x + 2/3 = 2 2/3 x + 1 combine like terms
2 1/3 x + 4 2/3 = 2 2/3 + 1

i know im suppose to solve for x but which x do i solve for. how do i eleminate one.
 

Denis

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Feb 17, 2004
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Re: ok this is how far i've gotten.

viva_la_isabel said:
im stuck. wat do i do next?
1/3 x + 4 + 2x + 2/3 = 2 2/3 x + 1 combine like terms
2 1/3 x + 4 2/3 = 2 2/3 + 1
i know im suppose to solve for x but which x do i solve for. how do i eleminate one.
Were you absent from class when this topic was covered?
Seems so. You need classroom help.
 

stapel

Super Moderator
Staff member
Joined
Feb 4, 2004
Messages
15,943
First, please confirm or correct my guess as to what the equation is. (We can't check your work if we can't tell what you're working on.)

Thank you.

Eliz.
 
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