If you know how to draw a straight-line - given the equation, the above section should be self-explanatory.Keisha said:On the sheet it says:
Solve the system by graphing
Then it says.....
we can graph the two lines as before. for 2x+y=2. two solutuions are (0,2) and (1,0). ,
For 2x+y=4, two solutuions are (0,4) and (2,0). Using these intercepts, we graph the two equations.
In the first equation,
if you put x= 0 --> you get y = 2
if you put y= 0 --> you get x = 1
Thus you get two points (0,2) and (1,0) to draw the first line.
similarly, you can get two points for the second line
There's a note that says In slope-intercept form, our equations are
the pictured graph shows 2 lines going diagonally \\ 2y+y=12 is at the top and 2x+y=4 is at the bottom.
Then it says: Notice that the slope for each of these lines is -2, but they have different y-intercepts. This means that the lines are parallel (they wil never intersect). because the lines have no points in common, there is no ordered pair that will satisfy both equations. The system has no solution. It is inconsistent.
I apologize for not knowing how to draw the graph on the computer.
It sounds as though you are not familiar with intercepts and/or how to graph straight lines. This should have been covered, in depth, well before you go to this topic! :shock:Keisha said:for 2x+y=2. two solutuions are (0,2) and (1,0). For 2x+y=4, two solutuions are (0,4) and (2,0). Using these intercepts, we graph the two equations.