Dirty.Rotten.Imbecile
New member
- Joined
- Jun 19, 2017
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- 21
Can someone check this equation for me to see if I got it right? The text book has the wrong solution.
When you plugged your answer back into the original equation, what did you get?Can someone check this equation for me to see if I got it right? The text book has the wrong solution.
I got a big long complex equation that was worse than the original problem!When you plugged your answer back into the original equation, what did you get?
How so? You plugged "-12/5" in for every instance of "x" on the left-hand side:I got a big long complex equation that was worse than the original problem!
How so? You plugged "-12/5" in for every instance of "x" on the left-hand side:
. . . . .\(\displaystyle \dfrac{3\left(-\frac{12}{5}\right)}{\left(-\frac{12}{5}\right)^2\, -\, 4}\, -\, \dfrac{2}{\left(-\frac{12}{5}\right)\, +\, 2}\)
You simplified the complex fraction in the usual manner:
. . . . .\(\displaystyle \dfrac{-\frac{36}{5}}{\frac{144}{25}\, -\, \frac{100}{25}}\, -\, \dfrac{2}{-\frac{12}{5}\, +\, \frac{10}{5}}\)
. . . . .\(\displaystyle \dfrac{-\frac{36}{5}}{\frac{44}{25}}\, -\, \dfrac{2}{-\frac{2}{5}}\)
. . . . .\(\displaystyle \left(-\dfrac{36}{5}\right)\left(\dfrac{25}{44}\right)\, -\, \left(\dfrac{2}{1}\right)\left(-\dfrac{5}{2}\right)\)
. . . . .\(\displaystyle \left(-\dfrac{9}{1}\right)\left(\dfrac{5}{11}\right)\, -\, (-5)\)
. . . . .\(\displaystyle \left(-\dfrac{45}{11}\right)\, +\, \dfrac{55}{11}\)
...and so forth. And you evaluated the right-hand side in the same way. What did you get?
Please reply showing your work. Thank you!