what1sth1s said:
1) Cheryl is 26 years older than her daughter Brooklyn. Last year, Cheryl was 2 years older than 7 times Brooklyn's age. How old are Cheryl and Brooklyn now?
all i did was:
Let x+2 = Cheryl
Let 7x = Brooklyn
2) Lisa has twice as many dimes as nickels. If there are 42 coins in total, how much money does Lisa have?
Next time, use a new thread for new problems...
1) Cheryl is 26 years older than her daughter Brooklyn. Last year, Cheryl was 2 years older than 7 times Brooklyn's age.
Go easy, step by step:
"Cheryl is 26 years older than her daughter Brooklyn."
B = Brooklyn, C = Cheryl ; then C = B + 26 : ok?
"Last year, Cheryl was 2 years older than 7 times Brooklyn's age."
Last year, Brooklyn = B - 1 and Cheryl = C - 1 : ok?
So C - 1 = 7(B - 1) + 2 : still with me?
C - 1 = 7B - 7 + 2
C - 1 = 7B - 5
C = 7B - 4 : understand?
And since C = B + 26, then:
7B - 4 = B + 26
Can you finish it?
2)Lisa has twice as many dimes as nickels. If there are 42 coins in total, how much money does Lisa have?
Step by step again:
"Lisa has twice as many dimes as nickels."
N = nickels; then dimes = 2N : easy nuff?
"If there are 42 coins in total, how much money does Lisa have?"
N + 2N = 42 : easy again?
Now solve for N, then figure out the total money: .05(N) + .10(2N)