george22 said:

:twisted:

I am frustrated with this problem: F = 1.8C + 32. If a student added 30 to twice the Celcius (F = 2C + 30) What error difference would he find?

I tried to use the formula: Error = 100 x [ __anticipated value - measured value__]

anticipated value

F<sub>Anticipated</sub> = 1.8C + 32

F<sub>Measured</sub> = 2C + 30

F<sub>Anticipated</sub> - F<sub>Measured</sub> = (1.8C + 32) - (2C + 30) = 2 - 0.2*C

(F<sub>Anticipated</sub> - F<sub>Measured</sub>)/F<sub>Anticipated</sub> = (2 - 0.2*C) / (1.8C + 32)

Looks like we need one more chunk of information. The original Celsius temperature would be the most convenient.