story problem: Reese has $225 in $10-bills and $5-bills

era

New member
Joined
Nov 30, 2006
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2
Please help me with this story problem:

Reese has $225 in ten dollar bills and five dollar bills. The number of five dollar bills is 15 more than the number of ten dollar bills. How many of each does he have? This is how I set it up, but I didn't get the right answer.

x= number of ten dollar bills
y=number of five dollar bills

10x(+15)+5y=225

Thanks!
 

arthur ohlsten

Full Member
Joined
Feb 20, 2005
Messages
854
let x = number $10 bills
let y= number $5 bills

but y=x+15 15 more $5 bills than $10 bills

10x +5y=225
but y = x+15
10x+5[x+15]=225
10x+5x+75=225
15x=150
x=10
then y=25

Arthur
 

era

New member
Joined
Nov 30, 2006
Messages
2
Thank you very much! :)
 

arthur ohlsten

Full Member
Joined
Feb 20, 2005
Messages
854
your welcome. Now that you see the approach, be sure to do it yourself.
You learn from the errors that you make.
Arthur
 
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