Stuck! Evaluate [e (f - 2)^2]/[ef] for e = -4 and f = 1

James5x5x

New member
Joined
Feb 25, 2017
Messages
4
Hi,

The answer to the equation below is apparently "1" but I just can't seem to get there. If anyone could show me step by step how you get the correct answer I'd really appreciate that. Thanks.

e(f — 2)²
______

ef


e = -4
f = 1​
 

MarkFL

Super Moderator
Staff member
Joined
Nov 24, 2012
Messages
1,312
First of all, we can simplify matters by observing \(\displaystyle e\) can be divided out:

\(\displaystyle \displaystyle X=\frac{e(f-2)^2}{ef}=\frac{e}{e}\cdot\frac{(f-2)^2}{f}=1\cdot\frac{(f-2)^2}{f}=\frac{(f-2)^2}{f}\)

Now, when you plug in \(\displaystyle 1\) for \(\displaystyle f\), what do you get?
 

JeffM

Elite Member
Joined
Sep 14, 2012
Messages
3,258
Hi,

The answer to the equation below is apparently "1" but I just can't seem to get there. If anyone could show me step by step how you get the correct answer I'd really appreciate that. Thanks.

e(f — 2)²
______

ef


e = -4
f = 1​
I'd like to help, but what is the equation?

\(\displaystyle \dfrac{e(f - 2)^2}{ef}\) is an expression, not an equation.

If you are supposed to evaluate the expression \(\displaystyle \dfrac{e(f - 2)^2}{ef}\ given\ e = -\ 4\ and\ f = 1\)

\(\displaystyle \dfrac{e(f - 2)^2}{ef} = \dfrac{(f - 2)^2}{f} = \dfrac{(1 - 2)^2}{1} = \dfrac{(-\ 1)(-\ 1)}{1} = \dfrac{1}{1} = 1.\)
 

James5x5x

New member
Joined
Feb 25, 2017
Messages
4
I got it. Thanks very much!
 
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