# Stuck! Evaluate [e (f - 2)^2]/[ef] for e = -4 and f = 1

#### James5x5x

##### New member
Hi,

The answer to the equation below is apparently "1" but I just can't seem to get there. If anyone could show me step by step how you get the correct answer I'd really appreciate that. Thanks.

e(f — 2)²
______

ef

e = -4
f = 1​

#### MarkFL

##### Super Moderator
Staff member
First of all, we can simplify matters by observing $$\displaystyle e$$ can be divided out:

$$\displaystyle \displaystyle X=\frac{e(f-2)^2}{ef}=\frac{e}{e}\cdot\frac{(f-2)^2}{f}=1\cdot\frac{(f-2)^2}{f}=\frac{(f-2)^2}{f}$$

Now, when you plug in $$\displaystyle 1$$ for $$\displaystyle f$$, what do you get?

#### JeffM

##### Elite Member
Hi,

The answer to the equation below is apparently "1" but I just can't seem to get there. If anyone could show me step by step how you get the correct answer I'd really appreciate that. Thanks.

e(f — 2)²
______

ef

e = -4
f = 1​
I'd like to help, but what is the equation?

$$\displaystyle \dfrac{e(f - 2)^2}{ef}$$ is an expression, not an equation.

If you are supposed to evaluate the expression $$\displaystyle \dfrac{e(f - 2)^2}{ef}\ given\ e = -\ 4\ and\ f = 1$$

$$\displaystyle \dfrac{e(f - 2)^2}{ef} = \dfrac{(f - 2)^2}{f} = \dfrac{(1 - 2)^2}{1} = \dfrac{(-\ 1)(-\ 1)}{1} = \dfrac{1}{1} = 1.$$

#### James5x5x

##### New member
I got it. Thanks very much!