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#### Guest

##### Guest

8+ t^3

factor the sum of cubes:

This is what i have done:

a^3 + b^3 = (a + b) (a^2 -ab + b^2)

t^3 + (2)^3

my book says the answer is

(2 + t) (4-2t + t^2)

Could someone explain how that became the answer besides what I did?

Thanks so much.