The trapazoid rule is

A = (b-a)/n*{.5(y<sub>1</sub> + y<sub>n+1</sub>) + sumy<sub>2 to n </sub>(y<sub>a</sub>)

y = x^2

The steps are 1/3

y<sub>1</sub>) = (1)^2 = 1

y<sub>2</sub>) = (4/3)^2 = 16/9

y<sub>3</sub>) = (5/3)^2 = 25/9

y<sub>4</sub>) = (6/3)^2 = 36/9

y<sub>5</sub>) = (7/3)^2 = 49/9

y<sub>6</sub>) = (8/3)^2 = 64/9

y<sub>7</sub>) = (9/3)^2 = 9

A = (3-1)/6*.5*(1+9)+(16+25+36+49+64)/9