Trigonometric Expression

Hello, flakine!

You're expected to know: .\(\displaystyle sin^2x\,+\,\cos^2x\:=\:1\quad\Rightarrow\quad\cos^2x\:=\:1\,-\,\sin^2x\)
. . Then this is one of the easier ones . . .

Verify the identity: .\(\displaystyle 2\cos^2x\,-\,1\:=\:1\,-\,2\sin^2x\)
On the left, we have: . \(\displaystyle 2\cos^2x\,-\,1\)
. . . . . . . . . . . . . . . . . . . . .\(\displaystyle \downarrow\)
Then we have: . . . \(\displaystyle 2(1\,-\,\sin^2x)\,-\,1\:=\:2\,-\,2\sin^2x\,-\,1\;=\;1\,-\,2\sin^2x\) . . . . there!
 
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