Trouble finding integral of a function

Feltzem

New member
Joined
Oct 31, 2015
Messages
1
I have simplified this function: y(x) = (2x3 (cos x)(sin √x)) / -x3 to this: -2(cos x)(sin √x). I then tried to find the area under the graph between 2 and 3.6.
Does the integral come out to -2(sin x)(-cos √x)? Because when calculating it with 3.6, minus that function with 2, I got 0.05573 instead of the correct answer of 2.66 (Grapher output).
Working
 
I have simplified this function: y(x) = (2x3 (cos x)(sin √x)) / -x3 to this: -2(cos x)(sin √x). I then tried to find the area under the graph between 2 and 3.6.
Does the integral come out to -2(sin x)(-cos √x)? Because when calculating it with 3.6, minus that function with 2, I got 0.05573 instead of the correct answer of 2.66 (Grapher output).
Working

Indefinite integral of this function [-2(cos x)(sin √x)] involves cannot be calculated in closed form (involves Fresnel's function - http://www.wolframalpha.com/input/?i=integral++(-2(cos+x)(sin+√x))dx)
 
Top