word problem, help please!

Kim

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Joined
Aug 31, 2005
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Farmer has 480 feet of fence to build a rectangular enclosure adjacent to a long barn. What are the dimensions (of rectangle) that MAXIMIZE the area?
I don't even know where to begin, can anyone please help?
 
confused

i still don't understand, which one do i use and what do i do with it? i'm sorry, just really confused. Thanks for replying, will you explain please?
 
My Take On It.

Hello Kim:

Hopefully you understand the diagram from the link that Elizabeth provided (the one with 192 feet and the river).

In your problem, the river is replaced by a barn.

Let x be the length of the two sides of the rectangle which touch the barn.

Since there is only 480 feet of fence available, the length of the side opposite of the barn has to be 480 - 2*x.

Hopefully you know that the area of this rectangle is:

A = x*(480 - 2*x)

Use the distributive property to simply:

A = -2*x^2 + 480*x

This is a quadratic equation of the form y = a*x^2 + b*x + c.

The graph of this area function is a parabola that opens downward. Therefore, the y-coordinate of the vertex represents the largest area.

The vertex occurs when x = -b/(2*a).

In your area equation, b = 480 and a = -2.

x = -b/(2*a) = 120.

This is one dimension. The side opposite the barn is 480 - 2*x. Substitute 120 for x.

480 - 2*120 = 240.

So, the dimensions of the rectangle are 240 feet by 120 feet.

Let us know if you need more help with this problem.

~ Mark
 
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