If a projectile is fired at a 45 degree angle from a height of 50 feet with an initial velocity of 100 feet per second, then its altitude A in feet after t seconds is given by A(t)=-16t^2+[100/sqaure root of 2]t +50.
How long will the projectile travel above 60 feet of altitude?
How long will it take for it to hit the ground?
Note: Round the solutions (t) to the lowest integers to simplify.
How long will the projectile travel above 60 feet of altitude?
How long will it take for it to hit the ground?
Note: Round the solutions (t) to the lowest integers to simplify.