word problem

Diana

New member
Joined
Mar 28, 2006
Messages
3
When the digits of a two-digit number are reversed, the new number is 9 more than the original number and the sum of the digits of the original number is 11. What is the original number?
 

skeeter

Senior Member
Joined
Dec 15, 2005
Messages
2,396
let x = tens digit of the original number
y = units digit of the original number
so, original number has the value (10x + y)

When the digits of a two-digit number are reversed, the new number is 9 more than the original number ...

digits reversed (the new number) ... 10y + x

the new number is 9 more than the original number ...

10y + x = 9 + (10x + y)

sum of the digits of the original number is 11 ...
x + y = 11

you should be able to solve the problem using the last two equations.
 

sagar1127

New member
Joined
Mar 27, 2006
Messages
20
could it be 56
 
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