#### orchidpsycho

##### New member

- Joined
- Sep 26, 2005

- Messages
- 41

y=x^2-5x+6

for the y I got

y=(0)^2-5(0)+6

y=6

(0,6)

On the x do i factor?

0=(x-5)(x-1)

5=x

1=x

(5,0) (1,0)

Not sure if thats what I do or not? any help would be appreciated.

- Thread starter orchidpsycho
- Start date

- Joined
- Sep 26, 2005

- Messages
- 41

y=x^2-5x+6

for the y I got

y=(0)^2-5(0)+6

y=6

(0,6)

On the x do i factor?

0=(x-5)(x-1)

5=x

1=x

(5,0) (1,0)

Not sure if thats what I do or not? any help would be appreciated.

- Joined
- Oct 1, 2005

- Messages
- 25

y=x^2-5x+6

should factor to

y=(x-3)(x-2)

Since (-3)(-2) = 6

and -3-2 = -5

Otherwise, I think you're ok.

- Joined
- Sep 26, 2005

- Messages
- 41

Thanks Again

- Joined
- Sep 26, 2005

- Messages
- 41

Don't you set each factor equal to 0 and solve

(x-3)=0

(x-2)=0

x=3,2