x,y intercepts

orchidpsycho

New member
Joined
Sep 26, 2005
Messages
41
The problem asks find the x and y intercepts of the graph of the equation

y=x^2-5x+6

for the y I got

y=(0)^2-5(0)+6
y=6

(0,6)

On the x do i factor?

0=(x-5)(x-1)

5=x
1=x

(5,0) (1,0)

Not sure if thats what I do or not? any help would be appreciated.
 

rahidz2003

New member
Joined
Oct 1, 2005
Messages
25
You picked the right methods for both intercepts, but I think you factored the expression incorrectly...

y=x^2-5x+6

should factor to

y=(x-3)(x-2)
Since (-3)(-2) = 6
and -3-2 = -5

Otherwise, I think you're ok.
 

orchidpsycho

New member
Joined
Sep 26, 2005
Messages
41
Thanks for pointing out my error. Don't know what I was thinking. The process is right though?

Thanks Again
 

Gene

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Oct 8, 2003
Messages
1,904
You didn't say what the points were after the corrected factorization, but you had them right for the wrong one so you probably got them right for the right one. Huh???
----------------------
Gene
 

orchidpsycho

New member
Joined
Sep 26, 2005
Messages
41
Actually I had them wrong I had (3,0) (2,0)

Don't you set each factor equal to 0 and solve

(x-3)=0
(x-2)=0

x=3,2
 

Gene

Senior Member
Joined
Oct 8, 2003
Messages
1,904
Yes, you do and you did.
(3,0) and (2,0) is correct.
 
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