# x,y intercepts

#### orchidpsycho

##### New member
The problem asks find the x and y intercepts of the graph of the equation

y=x^2-5x+6

for the y I got

y=(0)^2-5(0)+6
y=6

(0,6)

On the x do i factor?

0=(x-5)(x-1)

5=x
1=x

(5,0) (1,0)

Not sure if thats what I do or not? any help would be appreciated.

#### rahidz2003

##### New member
You picked the right methods for both intercepts, but I think you factored the expression incorrectly...

y=x^2-5x+6

should factor to

y=(x-3)(x-2)
Since (-3)(-2) = 6
and -3-2 = -5

Otherwise, I think you're ok.

#### orchidpsycho

##### New member
Thanks for pointing out my error. Don't know what I was thinking. The process is right though?

Thanks Again

#### Gene

##### Senior Member
You didn't say what the points were after the corrected factorization, but you had them right for the wrong one so you probably got them right for the right one. Huh???
----------------------
Gene

#### orchidpsycho

##### New member
Actually I had them wrong I had (3,0) (2,0)

Don't you set each factor equal to 0 and solve

(x-3)=0
(x-2)=0

x=3,2

#### Gene

##### Senior Member
Yes, you do and you did.
(3,0) and (2,0) is correct.