# y intercept -6 parallel to line 2x+3y+4=0

#### Guitarman

##### New member
Hello, I am asked to find an equation of the line that satisfies the given conditions.

y-intercept 6; parallel to the line 2x+3y+4=0

I use y=mx+b and get 3y=2x+4
then I believe its y=2/3 + 4/3

but what do i do now with the y intercept, etc.

thanks

#### stapel

##### Super Moderator
Staff member
Guitarman said:
parallel to the line 2x+3y+4=0

I use y=mx+b and get 3y=2x+4
How did you get "3y = 2x + 4"? Shouldn't there be a "minus" sign (or two) in there somewhere?

Eliz.

G

#### Guest

##### Guest
Hi there!!

As Stapel said, don't forget minus signs.

Using y = mx + b you should end up with:

$$\displaystyle \large\\y=-\frac{2}{3}x-\frac{4}{3}$$

Therefore, remember that in form y = mx + b
$$\displaystyle y=-\frac{2}{3}x+6$$