As per attached PLEASE explain Q 12 n 15
Thanking you
Thanking you
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Does "n" mean "and"? It's not a good idea to abbreviate in a math question, because every letter has a potential meaning!As per attached PLEASE explain Q 12 n 15
Thanking you
Hi My son is 6 but he is studying for 7 year entrance test, attached is a page from the book, which prepares the student for entrance examYou said in your prior post that your son is 6. These are not math questions for a 6 year old. These are questions for someone who has had 6 years of arithmetic.
Thanks for taking time to read. I was meaning please help explain Question 12 and Question 15 from the book ( I have the answer in the book, but I don't have detail explanationDoes "n" mean "and"? It's not a good idea to abbreviate in a math question, because every letter has a potential meaning!
But before I try to help, I'd like to have a better idea what kind of help is needed, so please show us what you/your son do understand about it, and make an attempt to solve the problems. See this summary of guidelines for submission.
In particular, is there a reason these two problems give you trouble, but others (which are similar) don't?
In question 12, they want the given fraction expressed as a percent.… please help explain Question 12 and Question 15 from the book …
Thanks a lot for your helpIn question 12, they want the given fraction expressed as a percent.
For example, what percent of pizzas are delivered hot, if 5/8ths of the pizzas are delivered hot?
5 ÷ 8 × 100 = 62.5%
In question 15, they've given the scale ratio as \(\displaystyle \dfrac{1 \text{unit model length}}{200 \text{unit real length}}\)
So any ratio of lengths model/real must equal 1/200. For example, if the model casts a shadow that is 3 cm long, then we would set up a proportion (i.e., two equal ratios) to find how long the real shadow would be.
\(\displaystyle \dfrac{3}{?} = \dfrac{1}{200}\)
One way to solve a proportion for the unknown part is to: (1) multiply on the diagonal and (2) divide by the number not used.
3 × 200 ÷ 1 = 600
The real shadow is 600cm long (6m).