At the theme park the average wait time is normally distributed with a mean of 9 minutes and standard deviation of 3 minutes. The average wait times are given in the table below.
Convert times of 7 minutes and 13 minutes to z-scores and sketch the graph of the time distribution on a bell curve with times of 7 minutes and 13 minutes indicated on the graph.
This is what I figured:
Z score = Measured value – mean / standard deviation
Measured values 7 and 13 (13 not part of table but are values to convert and place on the bell curve).
Mean given = 9 also is a Z value of 0
Standard deviation = 3
Z score = (7-9)/3 = -0.66667
Z score = (13-9)/3 = 1.333333
I attached the bell curve. The peak is represented by Mean = 9 and has a Z value of 0 with the 7 and 13 z scores on each side. Was my method and answer correct?
| Day | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
| Wait time (avg.) | 7 | 10 | 12 | 16 | 11 | 17 | 5 | 10 | 9 | 8 | 12 | 6 |
Convert times of 7 minutes and 13 minutes to z-scores and sketch the graph of the time distribution on a bell curve with times of 7 minutes and 13 minutes indicated on the graph.
This is what I figured:
Z score = Measured value – mean / standard deviation
Measured values 7 and 13 (13 not part of table but are values to convert and place on the bell curve).
Mean given = 9 also is a Z value of 0
Standard deviation = 3
Z score = (7-9)/3 = -0.66667
Z score = (13-9)/3 = 1.333333
I attached the bell curve. The peak is represented by Mean = 9 and has a Z value of 0 with the 7 and 13 z scores on each side. Was my method and answer correct?
