mathproblems
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- Oct 24, 2011
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Find the number of integer solutions of x1 + x2 + x3 = 15 subject to the conditions given.
0 < = x1 < 6,
1 < = x2 < 9,
x3 >= 0
c(15+3-1,15) –[ C(6+3-1,6) + C (7+3-1,7)+C(14+3,14,3)-C(1+3-1,1)]
Is this correct?
Thank you.
0 < = x1 < 6,
1 < = x2 < 9,
x3 >= 0
c(15+3-1,15) –[ C(6+3-1,6) + C (7+3-1,7)+C(14+3,14,3)-C(1+3-1,1)]
Is this correct?
Thank you.