cant post graph, so,,
2x-3y<=6
2x-3*0=6
2x=6x
x=3 (3,0)
2*0-3y=6
-3y=6
y=-2 (0,-2)
2*1-3y=6
2-3y=6
2-3y-2=6-2
-3y=4
-3y/-3=4/-3
y=-4/3 (1,-4/3)
this gives me my boundary line
and i just need to put in a couple test points in my equation
(0,0) or(5,-10) and this will tell me the side of the graph that
ineed to shade, am i right?
also, if i have 2x-3y,=12
x+5y<=20
x=0 meaning two boundary lines and two shaded areas,
do i just attack them the same way, just one at a time, more test points and the same conclusion?
thank you DAN
2x-3y<=6
2x-3*0=6
2x=6x
x=3 (3,0)
2*0-3y=6
-3y=6
y=-2 (0,-2)
2*1-3y=6
2-3y=6
2-3y-2=6-2
-3y=4
-3y/-3=4/-3
y=-4/3 (1,-4/3)
this gives me my boundary line
and i just need to put in a couple test points in my equation
(0,0) or(5,-10) and this will tell me the side of the graph that
ineed to shade, am i right?
also, if i have 2x-3y,=12
x+5y<=20
x=0 meaning two boundary lines and two shaded areas,
do i just attack them the same way, just one at a time, more test points and the same conclusion?
thank you DAN