Must you find an "equation", or would a "formula" be enough?I'm having a problem trying to find an equation for the following sequence if anyone could help me out.
4,6,9,12,14,17,20
Must you find an "equation", or would a "formula" be enough?
My fault, I'm seeking for a formula for this sequence.
Plus two, plus three, plus three; plus two, plus three, plus three; ....I'm seeking for a formula for this sequence.
Plus two, plus three, plus three; plus two, plus three, plus three; ....
No kidding? Seriously sir... I could figure this out myself...
I'm not sure if it's a 'formula' or an 'expression' that I want, to represent this sequence containing 'n' in it where 'n' represents an integer starting from 1 and onwards.
Example:
2,5,10,17...
is (n squared + 1), a quick question, does this represent Geometric Sequence?
No - for geometric sequence - the ratio is a fixed number (ref: http://en.wikipedia.org/wiki/Geometric_progression)
but I got no idea what is the 'formula' or 'expression' for this sequence:
4,6,9,12,14
where it increases by: 2,3,3 repeatedly
All I want is a formula/expression for this sequence containing 'n'.
One way to express it is by recursion:No kidding? Seriously sir... I could figure this out myself...
I'm not sure if it's a 'formula' or an 'expression' that I want, to represent this sequence containing 'n' in it where 'n' represents an integer starting from 1 and onwards.
Example:
2,5,10,17...
is (n squared + 1), a quick question, does this represent Geometric Sequence?
NO, a sequence of squares is neither geometric nor arithmetic - it is its own thing.
but I got no idea what is the 'formula' or 'expression' for this sequence:
4,6,9,12,14
where it increases by: 2,3,3 repeatedly
All I want is a formula/expression for this sequence containing 'n'.
One way to express it is by recursion:
\(\displaystyle \displaystyle a_1 = 4\)
\(\displaystyle \displaystyle a_2 = 6\)
\(\displaystyle \displaystyle a_3 = 9\)
\(\displaystyle \displaystyle a_n = a_{n-3} + 8\), for \(\displaystyle n>3\)
Another way to get it would be to use a function that gives the integer part of a division. I have seen the functiion "FLOOR" used in that way, but i don't know what language that is from. In Fortran (my language of choice!), the function is called INT, for "integer part of":
\(\displaystyle \displaystyle a_n = \mathrm{INT}\left[\dfrac{n\times 8 + 4}{3}\right]\)
Do you understand that this is exactly the answer that Stapel gave you? You originally said that you wanted to know how the sequence continued and that was exactly what Stapel gave.Great! thanks alot for your help. ^^
That's what I was looking for.
@Subhotosh Khan
Thanks for answering my quick question ^^