\(\displaystyle \displaystyle{ \sum_{n\, =\, 1}^{\infty} \,}\)\(\displaystyle \dfrac{4n^3}{6^{n+1}}\)
How to find a1, a2, a3. Is this function convergent and explain how?
What are "a1", "a2", and "a3"? Are they the first three summation terms (summing from n = 1 to n = 1, from n = 1 to n = 2, and from n = 1 to n = 3)? Or are they the addends of the series (so the sum from n = 1 to n = 3 is a1 + a2 + a3)? Or something else?\(\displaystyle \displaystyle{ \sum_{n\, =\, 1}^{\infty} \,}\)\(\displaystyle \dfrac{4n^3}{6^{n+1}}\)
How to find a1, a2, a3. Is this function convergent and explain how?