I am back
[MATH]\angle[/MATH]BOC [MATH]+ \angle [/MATH]COD [MATH]+ \angle[/MATH]EOD [MATH]=180^{o}[/MATH]
The bisector [MATH]\vec{OC}[/MATH] tells us that
[MATH]\angle[/MATH]BOC [MATH]= \angle [/MATH]COD
then
[MATH]2\angle[/MATH]BOC [MATH]+ \angle[/MATH]EOD [MATH]=180^{o}[/MATH]
Let [MATH]x = [/MATH] [MATH]\angle[/MATH]BOC
then
[MATH]2x + 3x + 5 =180^{o}[/math]
Find the value of [MATH]x[/MATH], then you can find [MATH]\angle[/MATH]AOE
Not that the graph or drawing is NOT to scale, and they made [MATH]\angle[/MATH]BOC looks smaller than [MATH]\angle[/MATH]COD to trick us while they are EQUAL