RandomUser8649764
New member
- Joined
- Jun 12, 2021
- Messages
- 14
Where did this come from? And are you sure you copied it exactly?View attachment 27782
So, I've been able to do very little, only able to cancel out some es with lns, to get
View attachment 27784
After that, I don't know what to do.
It wasn't. This one is different. there is not x² in the right hand side in this one, but there was in the last.This problem was already posted in Intermediate/Advanced Algebra earlier
this morning by RandomUser8649764, and Jomo commented about it.
From WolframView attachment 27782
So, I've been able to do very little, only able to cancel out some es with lns, to get
View attachment 27784
After that, I don't know what to do.
There is no y varriable. How can you know what y equals?From Wolfram
x ≈ -4.88864 and y ≈ -35.8913
Patience child.There is no y varriable. How can you know what y equals?
It is not an internet source, but it looks like thisPlease answer my questions. What reason do you have to think these problems are solvable algebraically? (Or are you satisfied with a numerical solution?) What is their source? Can you show us an image of the original so we can be sure they are copied correctly?
Is the context about solving algebraically, or about numerical methods (which is what Desmos or Wolfram Alpha will do)?It is not an internet source, but it looks like this
View attachment 27788
I don't know if it can be solved algebraically at all. I just know the the question asks, "solve the following for x"
I did.Ref: response #7
What is their source?
Can you show us an image of the original so we can be sure they are copied correctly?
The question sqesifically asks to solve for x. It does need to be solved agebreically.Is the context about solving algebraically, or about numerical methods (which is what Desmos or Wolfram Alpha will do)?
So it was given to you in handwritten form? By whom? (That is, what is your relationship with this person?)I did.
is the original
Then, what numerical methods do you know? Or are you allowed to use sites such as the two we've mentioned?The question specifically asks to solve for x. It does need to be solved algebraically.
No you did not!!I did.
is the original
What is their source?
Can you show us an image of the ORIGINAL so we can be sure they are copied correctly?
It was not printed ever. I got it from some one who sent like this. This is the original form. This is how I got it.No you did not!!
Where is the image of "original" - preferably from a printed source?
You said in an earlier post that it can be solved algebraically. How do you know that if you cannot do it? I suspect you are wrong.It was not printed ever. I got it from some one who sent like this. This is the original form. This is how I got it.
What I received was "solve for x" and nothing else. I might be wrong, everyone I've spoken to since having said that (both here and in the real world) have told me it can't.You said in an earlier post that it can be solved algebraically. How do you know that if you cannot do it? I suspect you are wrong.
No. What you have been told is that people doubt it can be solved algebraically. Have you tried Newton’s method?What I received was "solve for x" and nothing else. I might be wrong, everyone I've spoken to since having said that (both here and in the real world) have told me it can't.
Yes you canWhat I received was "solve for x" and nothing else. I might be wrong, everyone I've spoken to since having said that (both here and in the real world) have told me it can't.
Response #5x ≈ -4.88864