BigBeachBanana
Senior Member
- Joined
- Nov 19, 2021
- Messages
- 2,185
Prove that [imath]a^x-b^y=0[/imath], where [imath]x=\sqrt{\log_ab},\,y = \sqrt{\log_{b}a}[/imath] ; [imath]a,b >0\,\, \& \,\, a,b \neq 1.[/imath]
...since this line confused me for a ridiculous amount of timeSo xy = 1 or y=1/x = 1/sqrt(logab)
Therefore a continued violation would necessitate that my displacement from the interception of two orthogonal planes (both possessing a normal with negligible z components) ought to be reduced in magnitude?If you keep using those big words you're going to get yourself in trouble!