wavewavewow
New member
- Joined
- Apr 29, 2023
- Messages
- 1
Your image is huge, which makes it difficult to follow, and the writing is unclear. I *think* you have posted the following:Tom can build a bicycle in ten days. After four days of doing the job, his friend, Jerry joins him, and the two of them finished building the bicycle in three and a half days. How long will it take Jerry to build the bicycle alone?
Here is my solution: [huge image]
When you plugged your answer back into the original exercise, what did you get? (You can check the answer to *any* "solving" exercise by plugging it back into the original context.)Is my solution correct?
No, your solution is not correct.Tom can build a bicycle in ten days. After four days of doing the job, his friend, Jerry joins him, and the two of them finished building the bicycle in three and a half days. How long will it take Jerry to build the bicycle alone?
Here is my solution:
View attachment 35676
Is my solution correct? Thank you in advance!
as has already been pointed out (AHABPO)
It took me a bit to figure that one out.Does anybody know what "AHABPO" means? ?
IWHUTF ?I should have said that ITMABTFTOO
I would have used __ ___??IWHUTF ?
Nearly...I would have used __ ___??
I should have said that ITMABTFTOO
IWHUTF ?
I have no idea what those are ......... I think Stapel is on thesame rocky boat.I would have used __ ___??
Your "equation" holds good, of course, but I very much doubt if the OP would be able to solve it in the format you have provided; it might even confuse her/him further still! ?I prefer using units in the equation …
let [imath]t[/imath] be the number of days it takes Jerry to build a bike alone
[imath]\dfrac{1 \text{ bike}}{10 \text{ days}} \left(4+3.5 \right) \text{ days } + \dfrac{1 \text{ bike }}{t \text{ days}} \left(3.5 \text{ days }\right) = 1 \text{ bike done}[/imath]
solve for [imath]t[/imath]
Why did you write "equation"?Your "equation" holds good, of course, but I very much doubt if the OP would be able to solve it in the format you have provided; it might even confuse her/him further still! ?
If the "units" were to be removed, thus...
[math]\dfrac{1}{10}\times \left(4+3.5 \right) + \dfrac{1}{t}\times3.5 = \large{1}[/math]then s/he might be able to solve it (though, Ah ha'e ma doobts) but that wouldn't explain where s/he went wrong. ?
My only concern is that at the end you wrote 1 bike done instead of 1 bike.I prefer using units in the equation …
let [imath]t[/imath] be the number of days it takes Jerry to build a bike alone
[imath]\dfrac{1 \text{ bike}}{10 \text{ days}} \left(4+3.5 \right) \text{ days } + \dfrac{1 \text{ bike }}{t \text{ days}} \left(3.5 \text{ days }\right) = 1 \text{ bike done}[/imath]
solve for [imath]t[/imath]
just a habit ...My only concern is that at the end you wrote 1 bike done instead of 1 bike.