Please help!! I am trying to figure out the first derivative of the following equation
v=((ln(S/62))/-0.015)*S
To solve S for the first derivative of the curve when v = 0
I know the approximate answer from plotting the curve of the equation, but the ln fraction is throwing me off - I believe the 1st derivative of ln(S/62) should be 1/(S/62), but then what do I do with this, and what happens to the -0.015? I believe the derivative of the lone S = 1. I could of course be wrong on all fronts.
I just seem to be going in circles and getting totally stuck! would appreciate some help, are my assumptions even correct?
TIA
v=((ln(S/62))/-0.015)*S
To solve S for the first derivative of the curve when v = 0
I know the approximate answer from plotting the curve of the equation, but the ln fraction is throwing me off - I believe the 1st derivative of ln(S/62) should be 1/(S/62), but then what do I do with this, and what happens to the -0.015? I believe the derivative of the lone S = 1. I could of course be wrong on all fronts.
I just seem to be going in circles and getting totally stuck! would appreciate some help, are my assumptions even correct?
TIA
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