52 playing cards are divided to 3 people. What are chances that any player get excactly 2 x 9's and 2 x 6's?

[IsmoKerava]

Can anybody solve this? Should be easy, but seems impossible.

Question is following:

52 playing cards are divided to 3 people. What are chances, that any player get excactly 2 x 9's and 2 x 6's.

Can you solve this?

 

[Harry_the_cat]

What happens to the leftover card?

 

[Steven G]

Yes, helpers on this forum can solve this problem.
The main question is whether or not you can solve it.

This is a help forum where we helpers help students solve their problem(s). What helpers never do is solve a problem for a student--after all, that wouldn't be very helpful.

If you had read the forum guideline you would have known how to make a post and would have received help by now.

Please show us what you have done with this problem and/or where you are stuck.

 

[Steven G]

Hmm, 52 cards can't be divided evenly by 3 people (since 52/3 = 17 1/3).

Can we please see the exact problem?