The shape below has an area of [math]44 m^2[/math].
Find the value of [math]x[/math] ?
I tried as follows:
[math](2x \times x) + ( x \times [ (x+3)-x )] = 44 \\ \Rightarrow 2x^2 + 3x = 44 \\ \Rightarrow (x-4)(2x+11)=0 \\ \Rightarrow x = 4 \text{ since length is positive}[/math]I split the shape in two, a larger bottom rectangle, and a smaller top rectangle.
However the answer given as
Can anybody help with pointing out what I did wrong, as I do not understand the answer given.
Thanks
Find the value of [math]x[/math] ?
I tried as follows:
[math](2x \times x) + ( x \times [ (x+3)-x )] = 44 \\ \Rightarrow 2x^2 + 3x = 44 \\ \Rightarrow (x-4)(2x+11)=0 \\ \Rightarrow x = 4 \text{ since length is positive}[/math]I split the shape in two, a larger bottom rectangle, and a smaller top rectangle.
However the answer given as
Can anybody help with pointing out what I did wrong, as I do not understand the answer given.
Thanks