Angle Measurement/Equation

[alexanderdizon]

Please help me solve this. I just need help urgently. Thank you in advance.

 

[lev888]

How are BOD and EOD related?

 

[alexanderdizon]

How are BOD and EOD related?

BOD is EOD is linear pair. If added both, its 180 degrees.

 

[nasi112]

[MATH]2(3x + 5) + 2(180 - 3x - 5) = 360[/MATH]
angle BOC [MATH]= x[/MATH]
Can you find angle AOE, now?

 

[alexanderdizon]

Yeah, thank you very much. Could you pls explain bow did you come up with this equation, so ai can explain it later too. Cause we need to explain how did we solve it. Thank you very very much.

[MATH]2(3x + 5) + 2(180 - 3x - 5) = 360[/MATH]
angle BOC [MATH]= x[/MATH]
Can you find angle AOE, now?

 

[lev888]

BOD is EOD is linear pair. If added both, its 180 degrees.

Correct. That's your equation: the sum of those 2 angles is 180. Now you need to assign a variable to an angle, express the 2 angles through that variable using the 2 facts given in the problem, and solve the equation.

 

[alexanderdizon]

Yeah, thank you very much. Could you pls explain bow did you come up with this equation, so ai can explain it later too. Cause we need to explain how did we solve it. Thank you very very much.

 

[alexanderdizon]

Yeah, thank you very much. Could you pls explain bow did you come up with this equation, so ai can explain it later too. Cause we need to explain how did we solve it. Thank you very very much.

But I got 0 in the final answer. Does it mean 0 degrees?

 

[nasi112]

But I got 0 in the final answer. Does it mean 0 degrees?

ignore my posting. i think that i need to sleep

follow what lev888 said

 

[nasi112]

I am back

[MATH]\angle[/MATH]BOC [MATH]+ \angle [/MATH]COD [MATH]+ \angle[/MATH]EOD [MATH]=180^{o}[/MATH]
The bisector [MATH]\vec{OC}[/MATH] tells us that

[MATH]\angle[/MATH]BOC [MATH]= \angle [/MATH]COD

then

[MATH]2\angle[/MATH]BOC [MATH]+ \angle[/MATH]EOD [MATH]=180^{o}[/MATH]
Let [MATH]x = [/MATH] [MATH]\angle[/MATH]BOC

then

[MATH]2x + 3x + 5 =180^{o}[/math]
Find the value of [MATH]x[/MATH], then you can find [MATH]\angle[/MATH]AOE

Not that the graph or drawing is NOT to scale, and they made [MATH]\angle[/MATH]BOC looks smaller than [MATH]\angle[/MATH]COD to trick us while they are EQUAL

 

[alexanderdizon]

Thank you so much!