Please show us what you have tried and exactly where you are stuck.Hi, can someone provide a proof to:
For any a,b in a field F, prove using field axioms only that
-ab = a(-b) = (-a)b
Is this an automatic reply or is there something wrong with my post?Please show us what you have tried and exactly where you are stuck.
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In the attached, look at the last theorem.Hi, can someone provide a proof to:
For any a,b in a field F, prove using field axioms only that
-ab = a(-b) = (-a)b
Thanks a lot for your reply. Much appreciated.In the attached, look at the last theorem.
Yes - there is !! You did not follow instructions !!Is this an automatic reply or is there something wrong with my post?
ok, I should have stated that I had no idea how to start. I mean I started playing that fact that a + (-a) = 0 but could not break through towards the full proof.Yes - there is !! You did not follow instructions !!
What is not unique about 0 ?Thanks a lot for your reply. Much appreciated.
I went over the document (first path ) and it looks very clear.
Regarding theorem 2. Shouldn't it exclude the 0? That is,
theorem 2: For each a, not including 0, in the field, the -a is unique.
I take it back.What is not unique about 0 ?
Your definition sounds right to me. And it still applies to 0 as well as to any other a, doesn't it ?I take it back.
At first I did not understand the meaning of unique.
I believe that unique in this context means that for each "a" there is only one item (-a) that fulfills the condition a + (-a) = 0